InputfizzBuzz(5)
Output["1","2","Fizz","4","Buzz"]
InputfizzBuzz(3)
Output["1","2","Fizz"]
InputfizzBuzz(15)
Output["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

1 more hidden test cases - 4 in total will be graded.

Answer

function fizzBuzz(n) {
  const out = [];
  for (let i = 1; i <= n; i++) {
    let s = "";
    if (i % 3 === 0) s += "Fizz";
    if (i % 5 === 0) s += "Buzz";
    out.push(s || String(i));
  }
  return out;
}
fizzBuzz(5); // ["1", "2", "Fizz", "4", "Buzz"]

Building the string avoids a fourth i % 15 branch. n = 0 must return an empty array.

sandbox.js

function fizzBuzz(n) {
  // TODO
}

Output

Hit “Run tests” to check your solution.

All problems

Next question

JavaScriptEasy7/15

Write fizzBuzz(n) returning the FizzBuzz sequence from 1 to n as an array of strings

By FrontendPro Editorial Team Updated 8/7/2026

Explore the JavaScript interview guide

Examples

Write fizzBuzz so that the following cases hold.

InputfizzBuzz(5)
Output["1","2","Fizz","4","Buzz"]
InputfizzBuzz(3)
Output["1","2","Fizz"]
InputfizzBuzz(15)
Output["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]